Question

Using the following reaction, how many moles of gallium chloride will be produced if 5.42×10^-5 moles of gallium metal react with excess hydrochloric acid? Be sure to carefully balance the equation first.

Ga(s) + HCL(aq) -------> GaCl3(aq) + H2(g)

Answer 1

2Ga+6HCl-----> 2GaCl3+3H2

Let x be the number of moles of GaCl3 produced by 5.42*10^-5 moles of Ga

2 moles of Ga gives------> 2 moles of GaCl3

5.42*10^-5 moles of Ga gives----> x

Cross multiply

2x= 2*5.42*10^-5

X= 5.42*10^-5 moles of GaCl3