Solve the question GROUP PROBLEM SOLVING II Given: F (80 k N and F= {-80k} N...
Express Fas a vector in terms of the unit vectors i, j and k (present your answer with 3 significant figures). Please enter your answers in the form of Ai +Bj +Ck. z - F = 60 N 1101 40 50 Dimensions in millimeters Determine the angle in degrees between F and the y- axis. z - F = 60 N 1101 40 50 Dimensions in millimeters 300 mm 150 mm 200 mm Use the vector product treatment to express...
corresponding to the two forces acting F- 1-360j+270k) N Express it as a Cartesian vector. ine the couple moment corresponding to the two forces acting e pipe system shown at right. (10 marks) 0.4 m 0.3 m FB 1360j- 270k; N
please help solve for what is asked in orobkems A-H and the
free body diagrams as well. Will upvote if correct
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B 4 m 6 m 3 m 12 m 2 m F=80 N Determine the projected component of the force acting along the axis AB of the pipe. 60° A The 30kg pipe is supported at A by a system of five cords. Determine the force in each cord for equilibrium....
Class Test-II Phy-105-02 Fall 2019 Section-III: (Problem solving each carrying 2 marks; 2X5 =10) 21. Find the Young's modulus (Y) of the steel rod of 0.01 m long and a cross sectional area of 0.001 cm', elongates 0.1% when supported by a 100 kg load, hung from the other end. 22. Find the speed of water at the narrow end of a pipe through a cross section of 0.001 m when water flows from the other end of area 0.002...
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need your help solving this thermodynamics problem please:
Question Completion Status: QUESTION 1 20 points Save Ans The heat-pump system shown is designed to provide water-heating and space-cooling. The system includes a heat exchanger to subcool the R134a refrigerant at the outlet of the water heater while heating the refrigerant at the outlet of the evaporator. Given the following data, determine the enthalpy at each station, 1 through 6, using the R134a property tables (click here). Type your answers...
Can somone show me how to do the 1st problem? Need to
find the LS and SS for the fit and the LH and SH for the hole.
Fits are all SHAFT BASIS METRIC but the shaft and hole diameters can not be used right out of the table. This is because the 3mm shaft tolerance does not match. You will need to lookup the "Fit" from the table, and then use the LS (Largest Shaft) and SS (Smallest Shaft)...