Question

Q(1) During a chemical reaction, what defines when the concentrations of the reactants and products reach a constant level? A) Elementary process B) Rate constant C) Reversible reaction D) Equilibrium E) Rate law Q(2) Which is the correct equilibrium constant expression for the following reaction? FeO(s) + H2(g) - Fe(s) + H2O(g) A) Ke = [H2O] / [H2] B) Ke=[Fe][H2O] / [Fe2O3] [H2] C) Ke=[Fe) (H20] / [Fe2O3] D) Kc = [Hz] / [H2O] E) Ke= [Fe2O3] [H2] / [Fe][H2O] Q(3) Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine. CCl4(9) + (1/2)O2(g) - COCl2(g) + Cl2(g). Ke= 4.4 * 10 at 1,000 K Calculate Kc for the reaction 2CCl4(9) + O2(9) 2COCl2(g) + 2Cl2(g). A) 4.4 * 10 B ) 8.8 * 10° C ) 1.9 * 10 D) 1.9 * 10 E) 2.3 *10- Q(4) 1.75 moles of H2O2 were placed in a 2.50 L reaction chamber at 307°C. After equilibrium was reached, 1.20 moles of H2O2 remained. Calculate the equilibrium constant, Kc, for the reaction 2H2O2(g) +2H2O(g) + O2(g). A) 2.0 *104 B) 2.3*102 C) 2.4* 10- D) 5.5 * 100 E) 3.9 * 10- Q(5)The graph below represents the titration of? нз volume base added A) A strong polyprotic acid with a weak base. B) A strong polyprotic acid with a strong base. C) A strong monoprotic acid with a weak base. D) A strong monoprotic acid with a strong base. E) None of the answers is correct. Q(6) With reference to the graph of the titration in Q(5) what is the approximate pH of the solution when the concentration of acid and its conjugated base are equal? A) 2 B) 5 C) 9 D) 12 E) 14

Answer 1

Ans Daing ard podutts each eq wili buiun athemical eactione , when the conenlstalion the eactants a constantevel, this slate is called Fostuwand Reactio Rak Equillibsuum Point Barkwand Heacin Time Concentuotion oL Heactarts axe n the abo fiqwte, At t»o maximum and cencentstalivn produts ave minimum C z HO, Products ae notyet fomed As the eation proceccl Cencetsiatior Heactants Oe decreasing and oncentuatom of pxoducts ana intcasing UHimately a stage cones, when Hate f forwad eacken becemes equal to at obakwaxd neaction This stale called chemical equillhouium Hence, at equilibaum Jhe cencentration f J««actanls and producls ane censtart. The. CoTsect oplien iz (D Ans Guven chemical eguatien is - Feo Cs) H >>Fe Cs) H0 g) chemical equillihrium Apply the Law [Ho ke = ke Hee, fe cs I fe o co

Soli'd Or pue liquid molar Conceristatien o pua Reason Noe or tataken aj uerulant is - is Mola Conc Moles ofSubstance Volume Cin L) Mola cen Substance w ma W M Molaw Mar M X V 1 V XM ( d- duity M density Aubstonce moleculan mas ) fhe Substance Molar Cent a puu ubstan ce is Centant and moleulor mai As deraity aPartiular tmpouatuu ,thenefoe molan cone at Pune Substanco is coutant Can be wrt Hun a correct equllbwurn So, kc Corret opiom is A

Ans B Guiven steachion - the equaliom having kag = k equilibouum constart for 9.36 xI8 Hene, Correct oph Ang Criven chemital equatien gnilial moles tnilial 0M 11 Conc At equll moles At equill 0. 345 moles 0 SS At equill 0048M = 0.1 M Conc

apply the laus ol chemical eullibilm Now, ke = (0nda)C11) C0-48) 0 00532 O. a30 O 0 2310 ke 2.3 Xlo2 Hunce, the correct option s (B.