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If the Ka of the conjugate acid is 2.39 × 10-4 , what is the pKb...

If the Ka of the conjugate acid is 2.39 × 10-4 , what is the pKb for the base?

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Answer #1

Ka x Ky = lo-19 К, - Ka 14 KP 2-39 X1 K 41841009 X lo- log (Kh) P P -log (4.1841004xto 1) Pt 10.3783971

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