Question

10 pts) Draw Leis structures for each ion and determine hybridization and formal charges on fluorine and antimony atoms. Also, determine molecular geometries of each on. a) H2F b) SbF; (5 pts) Normal boiling point of benzene ( C6H6) is 80.1°C. If you add 0.15 moles of a nonvolatile solute to 250.0 g of benzene, what is the vapor pressure of the benzene at 80.1 °C? (5 pts) Ethylene glycol, (C2H6O2) used as an antifreeze. How many grams of ethylene glycol must be added to 1.0L of water to reduce the freezing point of the glycol-water mixture to -10.0°C? The freezing point depression constant of water is 1.86 (deg/molal)

Answer 1

10. Sol :-

# Hybridization (H) :- Number of bond pairs + Number of lone pairs

If H = 2, then Hybridization is sp

If H = 3, then Hybridization is sp²

If H = 4, then Hybridization is sp³

If H = 5, then Hybridization is sp³d

If H = 6, then Hybridization is sp³d²

If H = 7, then Hybridization is sp³d³

Now,

In H₂F⁺ , H = 2 + 0 = 2, therefore hybridization is sp and molecular geometry (not including lone pairs) is Bent.

In SbF₆^- , H = 6 + 0 = 2, therefore hybridization is sp³d² and molecular geometry (not including lone pairs) is Octahedral.

# Formal Charge (F.C) = Number of valance electrons (V) - Number of shared electrons (S)/2 - Number of unshared electrons (U)

So,

F.C of F in H₂F⁺ = 7 - 4/2 - 4 = 7 - 2 - 4 = 7 - 6 = +1

F.C of Sb in SbF₆^-  = 5 - 12/2 - 0 = 5 - 6 = - 1

(a). H2F C Fluoronium) !%. Lewis St suchowe V sp-Hybridization Bent Molecular Geometry (6) Hexa fluoro antimony Son! . معيا +عملو}s sاحييها n de spré-Hybridi TE 3 2 Spd - Hybridizaton Octahedral Molecular Geometry