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Your answer is partially correct. Try again. In the figure what is the net electric potential at the origin due to the circular arc of charge Q1- +3.53 pC and the two particles of charges Q2 3.1001 and Q3 -2.90Q1? The arcs center of curvature is at the origin and its radius is R 7.70 m; the angle indicated is 619.0 Qi 2.00R Number 9563 1Units

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Answer #1

Solution,

Electric potential, V = kq/r

Vn = (k/R) [Q1 + Q3 + Q2/2]

Vn = (9 x 10^9/7.7)[3.53 - 2.9 + 3.1/2] x 10^-12

Vn = 0.0025 V

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