Question

3. A 25.00 mL sample of 0.200 M nitrous acid is titrated with 0.300 M sodium hydroxide What is the pH of the solution when 10.00 mL of based has been added (K, = 4.6 x 104 for HNO.) 25 pts)

Answer 1

mmol of HNO2 = 25 ml x 0.20 m = 5 mmol mmol of NaOH = 10ml x 0.30 m = 3mmoll NAOH KNO NANO + H2O Total volume +3 = 35ml 3 Ilmmoll 3 5 c(mmol) -3 -3 E (mmol) - 2 vt forms a butter & pH can be calculated as -pH = pka + log contain both HNOL & NOND solution which follous- _pkaz -log ka = -log 4.6810? -pka : 3:34 = 3.34 + - - 3.34+ log [ 3mmol/3sme] [pH = 3.52 3 mmol /smi Lanmo/35m PH = 3.52 Scanned with CamScanner

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