Question

Azomethane, (CH3)2N2, decomposes in the gas phase to give ethane and nitrogen:

(CH3)2N2 (AZO) → C2H6 + N2

The overall pathway of AZO can be described as follows:

1. 2 AZOà AZO + AZO*      k1
2. AZO* + AZO à 2AZO       k2
3. AZO*à C2H6 + H2          K3

Derive overall reaction kinetics by using steady-state approximation, and discuss:

1. How to proceed the reaction as first-order for AZO
2. How to proceed the reaction as second-order for AZO

Answer 1

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The given reactions are :t DAME-D 2 A20 " AZO + A20* A zo’+ A 20 4 2 A20 AZO* *3 Cahat Hz combine o und @ ega we get 2 AZO A20 + 420* Now, as we know mat slowest step in nate determining step. Sun I nate = kg [Azo]" But Azot in an intermediate which in wamed during me neathon and allo delormed in me end of me Reachun. So, applying steady stale approximation; ki Lazog': K2 [A26][ Azo]*+ 163 [A203" 1,(A203= (162[420] + Kg ) (A 20°)* 2 CA zo] = K[Aza]? Kz [AZ] + K3 Now, put value of [Azul in can o we get

I rate= K, Kz (A20727 PANE-2 K2 [Azo]+ k3 This is me hnal nale law eah. Now we shidy nuo care here: care I :-) Thind step in me ineversible step and hence slowest step. so K272 K3 i nata i kj [A207 Kz (A20) 2 rate= ki k3 [ Azo] / K2 : L First under hon Azo. ] when K377) K₂ [420] nate = kiky [A2072 [CASE - 2 1C3 nule Ki[Azo)? Li second onder von Azo