Question

For question 1, complete chart in chart form please and then questions 2&3.

1. A student followed the procedure of this experiment to determine the K of zinc(II) iodate, Zn(IO) Solutions of Zn(NO), of known concentrations were titrated with 0.200 M KIO solutions to the first appearance of a white precipitate. The following data were collected: [Zn(NO),M 0.226 itial 0.101 0.0452 0.0118 [KIO M 0.200 0.200 0.200 initial 0.200 of Zn(NO,), mL V initial 100.0 100.0 100.0 100.0 V of KIO, added, mL 12.9 13.0 18.3 12.4 At endpoint: V total mL [Zn2 ], M [I0,], M [Zn2 ][IO,2 Log([Zn2 [I0,P) VIZN2 1+ [Zn2] Log K Graph using Equation 7.11, equal to Y-intercept sp K of Zn(I0), Equation 7.12 Which of the ion products found in question 1 is closest to the Ksp? Why? 2. The titration volumes for the first three samples in question 1 do not vary greatly. The titration 3. volume for the last sample, however, is considerably larger than that of the first samples. Why is this to be expected?

Answer 1

1000 given data [zn (NO3)2 ]initiae,M 0.226 Oolol 0,0452 0.0118 [KI03) initiae, M 0.200 0.200 0.200 0.200 Vinitial of Zn(NOx), ML 10010 10010 10010 12.9 1214 1310 1813 Vof KIO3 added, mL The total is filled with the following calculations: Totalva Vzn (NO3)2 +V K103 [zn+2)=[Zn(NO3)2] initial* vzn ( N03)2 / Vrotal [103-] = [K103] initial * V KI03/Vtotal [zn+2] * [103312 dogl[zn+234 [1023^2) (znze] fltr [znte] > A plot of the log data is made (czn+23+ [103-3^2) versus v [znte] /1+znt] Niznt?] /1+/cznty dog [?nt?] * [103]^2) 0,309 0,231 0, 167 -4,67 0,091 i -5,02 -3,97 -4,36

Login+?)(1-^2 205 0.0.15 0.2 25 013 035 Tum & -- Dog (2n+1] * [1-)^2 - Lineal (log [2n+2]*[1742nt2)2] * and you get the cut with the Yaxis, in this case - 514664 > The antilogarithm is calculated and you have KSP = Antidog (-504664). 3.42x10^-6]