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Question 20 of 34 > Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, H
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Answer #1

1st calculate the number of mol of Cl2

Given:

P = 775.0 torr

= (775.0/760) atm

= 1.0197 atm

V = 125.0 mL

= (125.0/1000) L

= 0.125 L

T = 25.0 oC

= (25.0+273) K

= 298 K

find number of moles using:

P * V = n*R*T

1.0197 atm * 0.125 L = n * 0.08206 atm.L/mol.K * 298 K

n = 5.213*10^-3 mol

From reaction,

Mol of MnO2 reacted = mol of Cl2 formed

= 5.213*10^-3 mol

Molar mass of MnO2,

MM = 1*MM(Mn) + 2*MM(O)

= 1*54.94 + 2*16.0

= 86.94 g/mol

use:

mass of MnO2,

m = number of mol * molar mass

= 5.213*10^-3 mol * 86.94 g/mol

= 0.4532 g

Answer: 0.453 g

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