Question

Answer the following questions based on the reaction below (5pts) 2 NaCl + Mgo - Na2O + MgCl2 What is the theoretical yield of sodium oxide fin grams) if 24.0 grams of sodium chloride reacts with 10.5g of magnesium oxide? (1.25pts) Ind na almol Nazo From na 22g Na 2 molt :.o. 2 mol Na From o imolo molwazo logo Imolo b. If 10.5 g of Na2O is formed during the reaction in part (a), what is the percent yield? (1.25pts) c. A student carried out the reaction in part (a) and got 92% yield of Na20. What is the student's actual yield? (1.25pts) 1 130 d. What is the theoretical yield if the reaction above is 98.0% efficient and yields 15.4 g Naz0 when 10.0 g of Mgo completely reacts with an excess of NaCI? (1.25pts)

Answer 1

Ans. Given reaction is written as - a Nace + Mgo - Nao + Mg Cla 2 (23 +35.5) (24716) (2x23+10) (24+2x355) = 117g = 40g = 629 Easg Calculation of theortical yield of Mayo first calculate the limiting steagent and the formation of Nego depends on the limiting mengent. According to abore Heaction - 117 g of Noll reacts with 40 g Mgo : 249 of lace will react with Mgo = 40 x 24 g of Mgo = 3:00 y of Mgo Given amount of Mgo is greater (r.e. 10.5g) than the Calculated amount. Hence Mgo is in excess amount and Nace is limiting reagent. Now, 117g of lace forms 62 g of Nago : 24g of all will form Nago = 62 x 24 g of logo = 12.72 g of Nowo 117 So, theoretical yield of Ngo is 12.72 g.

Actual yield of Nago = 10.5g Theoretical yield of plagos = 12.72g ofo yield - Actual yield y loo Theoretical yield 100 = 82-55% 10.5 12.72 So, the percent yield of the reaction is 82.55% o f the yield of the reaction is 92% Actual yield = ? % yield - Actual yield xloo . theoretical yield 98 = Actual yield x 100 12.72 Actual yield = 92 X 12.72 100 Actual yield = 11.70 g So, the actual yield of the greaction is 11.70 g

@ Theoretical yield of the eveaction = ? 98% efficient, reaction yields 15oug Hogo If Nall is in excess amount, so the yield of Nago depends on Mgo. 40 ч» 1 2 0 {м аа го : 10 g of Mgo will form = 62 x 10 g of Nago = 15:5g of Nomo (This is for 100% efficient Meaction ) for 100% efficient sreaction yield of Nogo is 155g So, for 98%, efficient reaction yield of Ngo = 15.5x98 g of No 100 = 15:19 4 So, theoretical yield of the reaction is 15.194