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SHOW WORK FOR THUMBS UP
5. M. Rudolph Inc. has an exposure to the price of steel. The price is currently at $50/coil. If the price remains the same o
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Answer #1

Only first 4 sup parts are being solved here.

a. Graph reflecting the relationship is copied below.

Data used for the graph:

Profit Price
7800000 61
8000000 60
8200000 59
8400000 58
8600000 57
8800000 56
9000000 55
9200000 54
9400000 53
9600000 52
9800000 51
10,000,000 50
10200000 49
10400000 48
10600000 47
10800000 46
11000000 45
11200000 44
11400000 43
11600000 42
11800000 41
12000000 40


Price 9200000 9400000 0000096 000000Or 10600000 11000000 11200000 10200000 10400000 10800000 11400000 11600000 7800000 8000

b. To hedge their risk, Rudolph will buy call option. Because Rudolph would like to lock in the price of steel and call option gives the right to Rudolph to buy steel at the desired price rather than relying on the market price which may rise upwards. Rise in steel price reduces the profits.

c. Management wants to ensure that profits are not reduced by more than 1,000,000. If the cost of the option is 100,000 then Rudolph needs to protect the price drop to avoid reduction by more than 1,000,000 - 100,000 = 900,000. The desired strike price needs to be 54 as the profit reduction is 800,000. It cannot be 55 as the profit reduction will be 1,000,000 and the total reduction will be 1,000,000+100,000 = 1,100,000 which is not desirable by the management.

d. If call option of $100,000 is purchased then the cash flow is as follows:

For price of $40, cash flow will be $12,000,000 - 100,000 = $11,900,000

For price of $45, cash flow will be $11,000,000 - 100,000 = $10,900,000

For price of $50, cash flow will be $10,000,000 - 100,000 = $9,900,000

For price of $55, cash flow will be $9,000,000 - 100,000 = $8,900,000

For price of $60, cash flow will be $8,000,000 - 100,000 = $7,900,000

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