Question

What concentration of Br" results when 691 mL of 0.797 M KBr is mixed with 947 mL of 0.431 M FeBr,? [Br"]= 0.750

Answer 1

This is mixing of the two salts. The complete calculation of the concentration is given as below:-

It is given that, volume of KBr = 691 mL = 0.691L. since, ImL = 10-3L. Concentration af KBr = 0.797 m =0.797 mol/L Number of moles af KBM = (0,691 L) X (0.797 mol/L) = 0.551 moles af kBr or Number of moles af Bre = 0.551 moles af Bi Further, we have volume af Fe Br2 = 947ML=0.9472 concentration affe Br2 = 0.431 mol/L Number of moles affeBr2 = (0.9472)x(0.431 mol/L) = 0.4l moles af Febr2

or Number of moles of RBn0 = 0.41 moles afen - © Total number of moles af en = (0,551 +0.41) molesolen number of moles af Bi = 0.961 moles af Bri Total volume (V)=(0.691 to 1947) L = 1.6382 So, the concentration of Br = 0.961 mole = 0.587 m. ar [899] = 0.587 mol/l = 0.587 m/ 1.6382