Find the pH of the equivalence point and the volume (mL) of 0.175 M HCl needed to reach the equivalence point in the titration of 65.5 mL of 0.234 M NH3.
Find the pH of the equivalence point and the volume (mL) of 0.175 M HCl needed...
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.125 M HCl needed to reach the equivalence point in the titration of 65.5 mL of 0.234 M NH3. Volume = mL HCl pH =
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.200 M HCl needed to reach the equivalence point in the titration of 65.5 mL of 0.234 M NH3.\ \ ]
Find the pH of the equivalence point and the volume (mL) of 0.0346 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO2. Find the pH of the two equivalence points and the volume (mL) of 0.0652 M KOH needed to reach them in the titration of 17.3 mL of 0.130 M H2CO3.
Find the pH of the equivalence point and the volume (mL) of 0.0558 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO2.
Find the pH of the equivalence point and the volume (mL) of 0.0372 M NaOH needed to reach the equivalence point in the titration of 42.2 mL of 0.0520 M CH3COOH. (K_a of CH_3COOH = 1.8 times 10^-5)
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.0702 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO,. Volume: mL KOH pH =
Be sure to answer all parts. Find the pH and the volume (mL) of 0.487 M HNO3 needed to reach the equivalence point in the titration of 2.65 L of 0.0750 M pyridine (C5HzN, Kb = 1.7 x 10-9). Volume = mL HNO3 pH-
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.0822 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO2. Volume: mL KOH pH =
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.0302 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO2.
QUESTION 12 Determine the volume in mL of 0.25 M HCl(aq) needed to reach the equivalence (stoichiometric) point in the titration of 47.3 mL of 0.29 M (CH3)3(aqXaq). The Kb of trimethylamine is 6.5 x 10-5. Enter your answer with two decimal places and no units.