For the next balance equation:
a) Calculate the concentration of [S] at a time in the reaction where [ES] = 0.09 mM if [S]0 was 2.55 mM.
b) What was [E]0 if at the same time [E] was 0.02 mM?
c) If the reaction is in equilibrium, calculate the equilibrium constant value for the reaction and the ratio between k1 and k-1.
Homework Answers
A) 2.55 - 0.09 =2.460
B) 0.02+0.09= 0.11
C) k= 0.09/2.46×0.02
=0.036
K={ES}/{E}×{S}......1
K-1={E}{S}/{ES}......2
K/k-1 =k2=( 0.036)2
= 0.0013
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