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30 o Water is poured into a container that has a small leak. The mass m of the water is given as a function of time t by m = 5.00px-3.00r + 20.00, with l 20, m in grams and 1 in sec- onds. (a) At what time is the water mass greatest, and (b) what is that greatest mass? In kilograms per minute, what is the rate of mass change at (c)-2.00s and (d)t-5.00 s?

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Ans: By taking first derivative of mass equation with respect to time and equating it to zero and solving for t will give the time at which the mass is greatest..

Ans m= 5 0-8-3大+20 (a) At iolud-tunt massis, Treatest? 서greated mass, 0.8- -0.2 ng 5 (4.214) 3(4.21)+ 20 23.16 g (e) Thuc atech mass chan乎袈-瑩62-3 (2) 6.23 R(2)ニ 0.0284 kg/min → t(5) R(5-0.00606 kgImuw

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