Homework Answers
integrated rate law for 2nd order reaction:
1/[A] = 1/[A]o + k*t
so, for 2nd order 1/concentration vs time is linear
integrated rate law for 1st order reaction:
ln [A] = –kt + ln [A]o
so, for 1st order ln(concentration) vs time is linear
integrated rate law for zero order reaction:
[A] = [A]o – k*t
so, for 0 order concentration vs time is linear
We have ln[sucrose] vs t as constant.
So, this is 1st order reaction.
Slope = -k
-0.208 hr-1 = -k
k = 0.208 hr-1
Rate law is:
Rate = k [sucrose]
Rate = 0.208 hr-1 [sucrose]
Answer: b
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The hydrolysis of sucrose (C12H22O11) into glucose and fructose in acidic water has a rate constant of 1.8×10−4s−1 at 25 ∘C. Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.40 L of a 0.160 M sucrose solution is allowed to react for 195 min .
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Sucrose, a sugar, decomposes in acidic solution to produce glucose and fructose. The reaction is first order in sucrose, and at 25 °C the rate constant is k = 3.60 x 10-3-1. If the initial concentration of sucrose is 0.050 M, what is the concentration after 2 days? O 0.042M 4.3 x 10-3M O 0.028 M 0.013 M
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