Question

In a survey on downloading​ music, a poll asked 724 internet users if they​ "ever downloaded music from an Internet site that was not authorized by a record​ company, or​ not," and 23​% responded​ "yes." Construct a 90​% confidence interval for the true proportion of internet users who have downloaded music from an Internet site that was not authorized. What is the confidence​ interval? Select the correct choice below​ and, if​ necessary, fill in the answer boxes within your choice. A. The 90​% confidence interval is left parenthesis nothing % comma nothing % right parenthesis . ​(Round to one decimal place as​ needed.) B. The conditions for constructing a confidence interval are not satisfied.

Answer 1

PAGE NO DATE: Ams Givem - Let a be the proportion of people Who have downloaded music from the an internet site that was not authorized Now, 23% Peoble 77% people say yes. say No. e = 0.23 [m= 724 ) Now, 90% Confindence interval for p is given by Le - (Z) (SE(A)) , p + (Z) (S. E(P) where A Proportion of success 2x z value at a significance Level S.EP2 - PCI-A Here x = 1-0.90= 0.10 - p = 0.23 SIE(A) = 16.23 (1-0.2 = V 724 /(0.23) (0.77). 724 S.E(P = 0.01564

(PAGE NO. DATE: Zo 10 = 1.645 I from Normal table] Now a substituting in formula 20:23 - (1.645) (0.01564) 0.23 + (1.645) (0.01564) 0.23 - 0.0257 a 0.23 +0.0257 / I o. 204279 0.255727] Round to decimal & E 10:20, 0.25] BLZ Like