Question

Question 16 of 26 > Attempt If 14.0 kg of A1,0,(s), 58.4 kg of NaOH(I), and 58.4 kg of HF(g) react completely, how many kilograms of cryolite will be produced? mass of cryolite produced: 57.64 kg Na, AIF Which reactants will be in excess? NaOH A1,0 HF What is the total mass of the excess reactants left over after the reaction is complete? total mass of excess reactants: 57645 MacBook Pro Q Search or enter website name R. E ?

Answer 1

Cryolite Naz Alfo Balanced Chemical Reaction Al2O3 + 12HF + 6 NaOH Imos 12 med 6 mol 2 Naz Alfo [2 mol Given Amant = 14 kg Al2O3 lux1000 gram = 58.4kg Naon 58.4 x1000 gram = 50.4 Kg HF & 58.4x1000 gram. mol of Alo3 = 14000 = 137.25 mol 102 of Naon - 58400g = 1460 mol mot of HF = 58400 g 2920 mol - 20g mot molar mass of Al2O3 = 27x2 + 16x3 = 54 +48 = 10 n .. . Naon = 23+16+1 =40 g/mol HF = 1+19 =

Step II. find Limiting Reagent - 137.25 mol O moles pee cofficient of A1, 0, - males (officient 137.25 = © males Pere Cofficient of NaOH = 146 omol = 243.33 @males Pere Cofficient of HF - 2920mol = 243.33 12 males her cofficient of Al2O₃ is levest. so it is limiting Reagento Step III. find mass of coyalite NaOH, HE tat that Conlume in Reaction. from POAC En RX dla O3 + 12 HF + 6 NaOH 2 Naz Alfo mofes of Naz Alfo = moles of Al2O3 Cofficient cofficient moles of Naz Alt6 = 137.25 2 mass of Naz Alfo = 137.25X2 malau mau (209.94) mass of Naz Alfo = 137.25 X 2 X 209.94 mass of cryolite = 5 7 6 28.53 = 57.6 kg

again POAC for Naon mass of Naoh = moles of AhO₂ molar mass (nox officient officient mass of Naon z 137.23 40 x 6 mass of Naoh = 137.23 x 4006 mass of HF = 32.9 kg again POAC for HF moles of Al₂O3 molar mass (20) X Lofficient officient mass of nf = 137.23 20 X 12 mass of HF = 32.9 kg steh III) mess of excess steegert = Remaning mass of Nach + Remaning mass of uf ( 58.4-32.9) +(58.4-32.9) 25.5+ 25.5 = 51 kq Thank you, May this help you.
POAC is the abbreviation used for Principle of Atom Conservation. It is very useful technique to solve the problems of 'chemical equations' quickly & accurately