Question

(3) What affect does the charge of the ion in solution have on the activity coefficient? How does this effect change as a fun
0 0
Add a comment Improve this question Transcribed image text
Answer #1

for any ionic solution ,ionic strength \mu is given by the summation of product of molality and (charge )2of the ith ion

suppose for example

AB2\rightleftharpoons A2+ +2B-

if m is the molailty of AB2 ,then the molatily of A2+ will be m and B-1 would be 2m since two ions of B is produced

charge of A is +2 and B is -1

so

μ = 1/2Σm;Ζ

where m =molality and Z =charge

for the above case

1 = 1/2(mAZ + mBZ)

u= 1/2(m * 22 + 2m * 12)

\mu = 1/2 (4m+2m)

\mu = 1/2 (6m)

\mu = 3m

thus ionic strength is \mu \propto Z^{2} so if charge increases ionic strength increases or vice versa

from the Debye Huckel limiting law

mean ionic activity is related to ionic strength as

-log\gamma_{i}=A \left | Z_{i}^{2 \right |\sqrt{\mu }

A = constant

3a) if charges increases then activity decreases or vice versa

B)-log\gamma_{i}\propto \sqrt{\mu }

if ionic strength increases then activity coefficient decreases as seen from the above relation

4) mean ionic activity does not depend whether it is cation or anion because what ever be the charge of the cation or anion , the charges will be squared and also we consider the mod value of the charges even if have  1 cation or anion (product of negative value and positive value is always negative value but the mod of negative value will always be positive.)

Add a comment
Know the answer?
Add Answer to:
(3) What affect does the charge of the ion in solution have on the activity coefficient?...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT