Question

The J.O. Supplies Company buys calculators from a Korean supplier. The probability of a defective calculator is 30%. If 14 calculators are selected at random, what is the probability that more than 6 of the calculators will be defective?

Answer 1

oues we have - Probability of befective (1) = 30 1oo 20.30 probability of non-Defective (a . > K0:30 e oito Therefore, weuse Binomial Distribution, D=14 Po let x denote the efet event the - Selecting the Calculator lot PC x76) = A PCX36) 3 1- 1 plx=0) + P(X=1) + f(x=2) + P(x=3) + f(x=4) + P(x=5) PC X=6)

V ENDULULLALLAH Date e r 13 - By using Binomial Dist" formula L P(x=x) = ncx pe ghose pab HP 6x=0) - 1460 (0-20) ° (0.70) - 0.00678 t°C X=1 ) = 1467 (0:30) (0.30.) - = 0.0377 - P(x=2) = 144 (0:30) ² (0.70) 0 •1/336 P(x-3) = 1462 (0:30) (0.70) " = 0:19433 P(x=4) = 1467 (030)* 10.90) - 2 0 2290 P(x=5) = 1465 20:30)70-90)9 - 0.19631 P ( X =6) = 146 (0.30)6 (070) ? - 0.12620 hence P(X76) = 1 [0.90 ] 리어의 o 2290