Question

Please and all two questions and explain how you got to your answer. I'm really lost and I have an exam in 7 days! A step by step would be appreciated.

8.(16 points) Draw the correct structures in the boxes provided. Hint: Work backwards. Br2 3 mol NaNH, CEH12 NaNH Bonus (5 points) Predict the products of the radical reaction shown below. Show the active intermediates that lead to each product. NBS Y - hv

Answer 1

3mol.eq. NaNH, CaH12 NH, to is group In this question the product is having tertiary alul group fe e so for that realtant should be haver tentiary group. Then by going reale albene to produce dibromo product which is undergo elimination reaction tool in the presence of sodemide so daamide followed by it undergo deprotanation by NaNta this it produce anion then it reales with allkyl halide to give the product.

NBS het ons You hr - Mellemtm : Mechantim Step 1 sigut per les Ni + BV stop-2 I N-BY + H-Bv r W-H & Bro X + Bri > M + HBV stop-3 Die + *-* - taong Sepete At For Afon + B** The NBS is the alleghit brominating agent going add Bv to the allylic position through the radical intermediate. E' NBS in presence beylet ho produce Br' which reacts with at allylic hydrogen to produce allghic radical followed celtacle of Bry to give allylie broninated product.