In a titration experiment, 9.3 mL of an aqueous
H2SO4 solution was titrated with 0.3 M NaOH
solution. The equivalence point in the titration was reached when
9.9 mL of the NaOH solution was added. What is the molarity of the
H2SO4 solution?
Balanced chemical equation is:
2 NaOH + H2SO4 ---> Na2SO4 + 2 H2O
Here:
M(NaOH)=0.3 M
V(NaOH)=9.9 mL
V(H2SO4)=9.3 mL
According to balanced reaction:
1*number of mol of NaOH =2*number of mol of H2SO4
1*M(NaOH)*V(NaOH) =2*M(H2SO4)*V(H2SO4)
1*0.3*9.9 = 2*M(H2SO4)*9.3
M(H2SO4) = 0.1597 M
Answer: 0.16 M
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