"Compute the depreciation each year of a machine that costs $68,000 to purchase and $3,100 to install with 10 years of life. Use DDB method (multiplier = 2) switching to straight line depreciation when appropriate. Assume a salvage value of $0. How much should be depreciated in year 8?"
| Purchase Cost | $68,000 | |||||
| Installation Cost | $3,100 | |||||
| Total Cost | $71,100 | |||||
| Year | DDB Method | Remaining value | Straight line method | |||
| 1 | 71,100*20% = 14,220 | 71,100 - 14,220 = 56,880 | 71,100/10 = 7,110 | |||
| 2 | 56,880*20% = 11,376 | 56,880 -11376 = 45504 | 56,880/9 = 6,320 | |||
| 3 | 45,504*20% = 9,100.8 | 45,504 - 9100.8 = 36403.2 | 45,504/8 = 5,688 | |||
| 4 | 36403.2 *20% = 7,280.6 | 36,403.2- 7,280.6 = 29122.6 | 36,403.2/7 = 5,200.5 | |||
| 5 | 29,122.6*20% = 5,824.5 | 29,122.6 - 5,824.5 = 23,298 | 23,298/6 = 3,883 | |||
| 6 | 23,298*20% = 4,659.6 | 23,298 - 4,659.6 = 18,638 | 23,298/5 = 4,659.6 | |||
| In year 6 the depreciation value is same for both method and in 7th year DDB depreciation value is lesser than SLM depreciation method hence we switched to SLM method from year7. At year 8 depreciation value is $ 4,659.5 | ||||||
| Depreciation using SLM in year 7 | 18,638/4 = 4,659.5 | |||||
| Remaining value | ||||||
| 7 | 18,638*20% = 3,727.7 | 18,638 - 3,727.7 = 14910.8 | 18,638.4/4 = 4,659.6 | 18,638 - 4,659.5 = 13978.4 | ||
| 8 | 14910.8 *20% =2,982.1 | 14910.8 - 2,982.1 = 11928.6 | 14,910.8/3 = 4,970.3 | 13,978 - 4,659.5 = 9,318.9 | ||
| 9 | 11,928.6*20% = 2,385.7 | 11,928.6 - 2,385.7 = 9542.9 | 11,928.6/2 = 5,964.3 | 9,318.9 - 4,659.5 = 4,659.4 | ||
| 10 | 9,542.9*20% = 1,908.6 | 9,542.9 - 1,1908 =7634.3 | 9,452.9/1 = 9,452.9 | 4,659.4- 4,659.5 = 0 | ||
| Depreciation applied for each year | ||||||
"Compute the depreciation each year of a machine that costs $68,000 to purchase and $3,100 to...
using excel show the formulas
0/1 pts Question 2 "Compute the depreciation each year of a machine that costs $55,000 to purchase, and $4,200 to install with a 10-year life. Use DDB method (multiplier 2) switching to straight line depreciation when appropriate. Assume a salvage value of $14,000 How much should be depreciated in year 7?" ered 4,402 nswers 380 (with margin: 4)
Compute depreciation for each year (and total depreciation of
all years combined) for the machine under each depreciation
method.
A machine costing $212,600 with a four-year life and an estimated $17,000 salvage value is installed in Luther Company's factory on January 1. The factory manager estimates the machine will produce 489,000 units of product during its life. It actually produces the following units: 122,800 in Year 1, 122,900 in Year 2, 120,500 in Year 3, 132,800 in Year 4. The...
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Problem 10-2A Depreciation methods LO P1 A machine costing $209,800 with a four-year life and an estimated $19,000 salvage value is installed in Luther Company's factory on January 1. The factory manager estimates the machine will produce 477,000 units of product during its life. It actually produces the following units: 121,800 in 1st year, 122,700 in 2nd year, 119,800 in 3rd year, 122,700 in 4th year. The total number of units produced by the end of year 4 exceeds the...
A machine costing $210.400 with a four-year life and an estimated $16,000 salvage value is installed in Luther Company's factory on January 1. The factory manager estimates the machine will produce 486,000 units of product during its life. It actually produces the following units: 121,700 in Year 1, 122,600 in Year 2, 120,600 in Year 3, 131,100 in Year 4. The total number of units produced by the end of Year 4 exceeds the original estimate-this difference was not predicted.(The...
A machine costing $216,600 with a four-year life and an estimated $19,000 salvage value is installed in Luther Company's factory on January 1. The factory manager estimates the machine will produce 494,000 units of product during its life. It actually produces the following units: 121,700 in 1st year, 123,000 in 2nd year, 121,500 in 3rd year, 137,800 in 4th year. The total number of units produced by the end of year 4 exceeds the original estimate-this difference was not predicted....
Problem 8-2A Depreciation methods LO P1 A machine costing $206,600 with a four-year life and an estimated $15.000 salvage value is installed in Luther Company's factory on January 1 The factory manager estimates the machine will produce 479,000 units of product during its life. It actually produces the following units: 123.000 in 1st year, 123,500 in 2nd year, 121,400 in 3rd year, 121,100 in 4th year. The total number of units produced by the end of year 4 exceeds the...
Problem 8-2A Depreciation methods LO P1
A machine costing $213,600 with a four-year life and an
estimated $18,000 salvage value is installed in Luther Company’s
factory on January 1. The factory manager estimates the machine
will produce 489,000 units of product during its life. It actually
produces the following units: 122,800 in Year 1, 122,700 in Year 2,
120,000 in Year 3, 133,500 in Year 4. The total number of units
produced by the end of Year 4 exceeds the...
Problem 8-2A Depreciation methods LO P1 A machine costing $213.000 with a four-year life and an estimated $15,000 savage value is installed in Luther Company's factory on January 1. The factory manager estimates the machine will produce 495.000 units of product during its life. It actually produces the following units: 122,500 in Year 1 124,300 in Year 2, 120.700 in Year 3, 137,500 in Year 4. The total number of units produced by the end of Year 4 exceeds the...