Question

62. The numbers preceding the formulas in chemical equations are referred to as the coefficients. 63. PCI3 can be produced from the reaction of P4 with Cl2 Pa(s)+6 Cl2(g)-4 PCI3(g) If 1.00 g P4 reacts with 1.00 g Cl2, which reactant is the limiting reactant? What mass of product may be produced? Indicate the answer choice that best completes the statement or answers the question. 64. How many moles of sodium bromide can be produced from the reaction of 1.03 moles of sodium with 0.650 moles of bromine gas? 2 Na(s)+ Br2(g)-2 NaBr(s) a. 0.650 mol b. 1.03 mol c. 1.30 mol d. 2.06 mol e. 0.515 mol 65. What mass of iron can be produced from the reaction of 175 kg Fe2O3 with 385 kg CO?" Fe2O3(s)+3 CO(g)-2 Fe(s) +3 CO2(g) b. 30.6 kg a. 2.19 kg c. 61.2 kg d. 122 kg e. 512 kg 66. If 5.00 g Br2 and 1.10 g NH3 react according to the equation below, what is the maximum mass of ammonium bromide produced? 3 Br2()+8 NH3(g)6 NH4Br(s) +N2(g) b. 6.13 g d. 4.74 g e. 8.43 g a. 3.06 g c. 12.9'g 67. Aspirin (CoHgO4) is produced by the reaction of salicylic acid (M = 138.1 g/mol) and acetic anhydride (M= 102.1 g/mol). C7H6O3(s)+ C4H6O3()-CgHsOs(s) + C2H402() If you react 2.00 g C7H6O3 with 1.60 g C4H6O3, what mass of aspirin (M 180.2 g/mol) can theoretically be obtained? a. 0.40 g e. 3.60 g d. 1.53 g c. 2.82 g b. 2.61 g 68. How many moles of Mg3P2(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol Pa(s)? 6 Mg(s) + P4(s)-2 Mg3P2(s) a. 0.047 mol d. 0.020 mol e. 0.040 mol c. 0.42 mol b. 0.14 mol 69. If 50.6 g of O2 is mixed with 50.6 g of H2 and the mixture is ignited, what is the maximum mass of water that may be produced? a. 455 g e. 90.0 g d. 101 g c. 50.6 g b. 56.9 g 70. The commercial production of phosphoric acid, H3PO4, can be represented by the equation 1150 g 300 g 304 g 300 g 1500 g 3CaSiO3 + 5CO2 + 2H3PO4 ЗН-0 502+ 5C + 3SIO2+ 60.1 g/mol 12.0 g/mol 32.0 g/mol 18.0 g/mol Ca3(PO4)2+ 310 g/mol The molar mass for each reactant is shown below the reactant, and the mass of each reactant for this problem is given above. Which substance is the limiting reactant? a. H2O e. SiO2 d. Cas(PO4)2 b. С c. O2 Page 9

Answer 1

62. Stoichiometric 63. Ig P4 x Imole P4 x = 4.436g Plz 4 mole Plz X I mole P4 137.33g Pelz I mole Plz IN 123.90g Igų * Imole ų x 4 mole Pllz x 6 mole ų 137.33g PUz = 1.29g Plez Imole Pų 70.906 g it produces lesser 3 is limiting reactant because amount of Plez Mass of product produced = 1.299 Plz = 1.03 mole NaBr 1.03 mole Na x 2 2 mole NaBr mole Na Bry 0.650 mole Br x 2 mole Nabr = 1.3 mole I mole br, since Na is limiting Moles y Nabr formed =1.03 mae (b) 175 kg Fehoz xi mole FeO3 x 2 mole Fe X 55.845 g - Indle feą Imole fe = 122.398 g kg 385kg co x I indle co x a mole fex 55.845 g 28.01g 3 male co i male te = 511.729 kg → Fe₂O₃ is limiting. so mass y se produced a 122 kg (d)