After surveying brokers at an insurance firm, the results showed that out of 6 brokers only 30% of the brokers were bringing in most of the sales, while the remainders were only able to renew with their same companies. I claim that 50% of all brokers are able to bring in most of sales. Use a 0.05 significant level to test the stated claim about population proportion." In your second posting, you need to manually state the null and alternate hypotheses for the claim you have made in your question and type of hypothesis test, by indicating whether the test is right-tailed, left-tailed, or two-tailed test. Then, calculate the related Test Statistic and p-value by StatCrunch along with the summary table or by using manual calculations followed by comparing the related p-value versus the level of significance to determine whether to reject or not to reject the null hypothesis. Based on this comparison, you can make a decision whether the stated claim inside your question about the population proportion is valid or not.
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: P = 0.50
Alternative hypothesis: P 0.50
Note that these hypotheses constitute a two-tailed test.
Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method, shown in the next section, is a one-sample z-test.
Analyze sample data. Using sample data, we calculate the standard deviation (S.D) and compute the z-score test statistic (z).
S.D = sqrt[ P * ( 1 - P ) / n ]
S.D = 0.20412
z = (p - P) /S.D
z = - 0.9798
where P is the hypothesized value of population proportion in the null hypothesis, p is the sample proportion, and n is the sample size.
Since we have a two-tailed test, the P-value is the probability that the z-score is less than -0.9798 or greater than 0.9798.
Thus, the P-value = 0.3272
Interpret results. Since the P-value (0.3272) is greater than the significance level (0.05), we cannot reject the null hypothesis.
From the above test we have sufficient evidence in the favor that stated claim inside your question about the population proportion is valid
After surveying brokers at an insurance firm, the results showed that out of 6 brokers only...
ONLY DO NUMBER 3 For this project you will test claims and conjectures using hypothesis testing. For each hypothesis test, report the following: The null hypothesis, H0 The alternative hypothesis, H1 The test statistic rounded to the nearest hundredth (use T Stats or Proportion Stats in StatCrunch to find test statistics) The P-value for the test (use T Stats or Proportion Stats in StatCrunch to find P-values) The formal decision (Reject H0 or Fail to reject H0, remember that reject...
ONLY DO NUMBER 7 For this project you will test claims and conjectures using hypothesis testing. For each hypothesis test, report the following: The null hypothesis, H0 The alternative hypothesis, H1 The test statistic rounded to the nearest hundredth (use T Stats or Proportion Stats in StatCrunch to find test statistics) The P-value for the test (use T Stats or Proportion Stats in StatCrunch to find P-values) The formal decision (Reject H0 or Fail to reject H0, remember that reject...
A survey of 1,680 randomly selected adults showed that 549 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 37% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts a through e Sample proportion: 0.326786 Test statistic Critical z: P-Value z:-3.6687 ± 2.5758 0.0002 a. Is the test...
PLEASE
HELP ME OUT WITH BOTH QUESTIONS!!!
it is greatly appreciated!! thank you so much. no need to show
the work.
You wish to test the claim that the average IQ score is less than 100 at the .005 significance level. You determine the hypotheses are: Ho:u= 100 H1:4 < 100 You take a simple random sample of 72 individuals and find the mean IQ score is 96.7, with a standard deviation of 15.5. Let's consider testing this hypothesis two...
A poll of 2,142 randomly selected adults showed that 92% of them own cell phones. The technology display below results from a test of the claim that 91% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.91 vs p≠0.91 Sample X N Sample p 95% CI Z-Value P-Value 1 1970 2,142 0.919701 (0.908193,0.931210) 1.57 0.117 a. Is the...
6. A claim is made that college students spend 75% of their time on either sleeping or socializing. You do not believe this claim, and you set out to conduct a hypothesis test with the following hypotheses: Ho: p = 0.75 vs. Ha: p ≠ 0.75. If you gather data from a sample and compute a test statistic equal to -0.6, what would the p-value be? 7. Return to Question 6. The fact that the test statistic is negative tells...
A machine that puts corn flakes into boxes is adjusted to put an average of 15 ounces into each box, with a standard deviation of 0.25 ounce. The distribution of ounces per box has a normal distribution. If a random sample of 12 boxes had a sample standard deviation of 0.38 ounce, does this data support the claim that the standard deviation has increased and the machine needs to be adjusted. Use a 0.01 level of significance. This problem is...
In Exercises 4-6, do the following a) State the null and alternative hypotheses, and identify which represents the claim. b) Determine when a type I or type Il error occurs for a hypothesis test of the claim. c) Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. d) Explain how you should a decision that rejects the null hypothesis e) Explain how you should interpret a decision that fails to reject the null hypothesis. 4. A news outlet reports...
A certain drug is used to treat asthma. In a clinical trial of the? drug, 26 of 255 treated subjects experienced headaches? (based on data from the? manufacturer). The accompanying calculator display shows results from a test of the claim that less than 99?% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.01 significance level to complete parts? (a) through? (e) below. a. Is the test? two-tailed, left-tailed, or?...
A randomly selected sample of 32 individuals reported that their smartphone stopped working after an average of 4.2 years. Assume that we know the population standard deviation of smartphone life expectancy is 1.2 years. Test the claim that the average smartphone life expectancy is less than 4.7 years (the average based on past studies). Use a 0.01 significance level. 1) State the Null Hypothesis, Alternate Hypothesis, type of test & level of significance (2 pts) 2) Check the conditions. (2 pts)...