Question

which we can write as: E, E k Similarly, the electric fieldE2 from the charge-Q at x x0 has xo replaced by "Yo: Add these together to find the x component of the total electric field from both charges: Notice that the field component in the y direction is zero at the locations of interest, and that the field at that location is in the + x direction. At the origin, the field is then given by Equation (1) for y, 0: - om) FRe o At y 3.00 cm, Equation (1) gives instead: (3) 티y = 0.03 m)-ke-2 + (0.03m)2 The ratio-squared of the magnitude of the field is: E (0.03 m) 12( | E(0 m) | 2 [(x0)2 + (0.03 m)2]3/2 (0.04 m)3 /2 [(0.04 m)2 + (0.03 m)2 :0512 Since there were 100 field lines per cm2 at y 0, there should be E O.03 m) 12 100 ×

Answer 1