A spring-block system sits on a horizontal, frictionless surface. The spring has a spring constant k =2000N/m. The mass of the block is 14.5 kg. The spring is stretched out a distance of 20.0 cm and released. The block undergoes simple harmonic motion with a phase constant φ=?.
a) if the velocity of the block is -2.00 m/s at t= 0.150 s, what is the phase constant?
b) determine the acceleration of the block at t = 0.150 s.
c) what is the potential energy at t =0.15s?
d) what is the kinetic energy at t=0.15s?
e) what is the total energy at t=0.15s?
A spring-block system sits on a horizontal, frictionless surface. The spring has a spring constant k...
A spring-block system sits on a horizontal, frictionless surface. The spring has a spring constant k =2000N/m. The blocks mass is 10.0kg. The mass of the spring is negligible. The spring is stretched out a distance of 20.0 cm and released. The block undergoes simple harmonic motion with a phase constantf= 1.35 rad. a) determine the timeit takes for the spring to be compressed 6.50cm after it was released b) determine the acceleration of the black at t = 1.50 s.
A block of mass 6.00kg is connected to a spring on a horizontal frictionless surface. By stretching the block and then releasing it, the block-spring system undergoes simple harmonic motion. The block’s position as a function of time is given by x = 45.0 cm cos(3pi(t) - pi/3) a. Determine the angular frequency and period of the motion b. Determine the amplitude c. Determine the phase angle e. Determine the time when the position x = -18.0cm f. Determine the...
2.0 kg block on a horizontal frictionless surface is attached to a spring whose force constant is 590 N/m. The block is pulled from its equilibrium position at x = 0 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along a horizontal x-axis. What is the period (in s) of the resulting motion?
A 0.39-kg block on a horizontal frictionless surface is attached to an ideal spring whose force constant (spring constant) is 540 N / m. The block is pulled from its equilibrium position at x=0.000 m to a displacement x=+0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the block's position is x=0.057 m, its kinetic energy is closest toA. 1.0 J.B. 0.85 JC. 0.80 JD. 0.95 J.E. 1.1 J.
a 4.5 kg block on a horizontal frictionless surface is attached to an ideal spring whose force constant (spring constant) is 450 N. The block is pulled from its equilibrium position at x=0.000 m to a position x=+0.080 m and is released from rest. The block then executes harmonic motion along the horizontal x-axis. The maximum kinetic energy of the system is closest to _____?
1. A block of mass 6.00kg is connected to a spring on a horizontal frictionless surface. The spring constant is 280N/m. The block-spring system undergoes simple harmonic motion. At a time t=0s, the position of the block x= +A and its velocity vx= 0. At t=2.50s the position x = -12.0 cm No credit awarded without correct units! a. Determine the angular frequency and period of the motion b. Determine the amplitude c. Determine the phase angle d. Write the...
A spring of spring constant k=261 N/m is attached to a block of mass 1.38 kg and stretched horizontally to a position 15.0 cm from the springs equilibrium position. The spring and mass are released and oscillate in simple harmonic motion across a frictionless horizontal surface. What is the maximum speed obtained by the mass? m/s
A 1,28-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 133,84 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a displacement x = +0,03 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. What is the velocity of the block at time t = 0,34 s? Answer in two decimal places.
A 1,11-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 100,28 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a displacement x = +0,04 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. What is the velocity of the block at time t = 0,23 s? Answer in two decimal places.
A 2.00 kg frictionless block is attached to a horizontal spring
as shown. Spring constant k = 200.00 N/m. At t = 0, the position x
= 0.225 m, and the velocity is 4.25 m/s toward the right in the
positive x direction. Position x as a function of t is: x =
A*cos(?t + theta) , where A is the amplitude of motion and ? is the
angular frequency discussed Chapter 11 and the notes. Theta is
called the...