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number 3 and 4 please
2. The Ksp of bismuth iodide, Bil; Molar Mass = 589.68], is 8.1 x 10. If Bilz (s) is dissolved in pure water, what is the s
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3 + Bi Iz (5) - Bila + 3 I (aq) S 35 kop= (Bi3t) [I-J3 = (8) (35) - 2754 8.1x1019-2754 s4= 3x10-20 -5 o s = 1.32 x 10 mollutBi Is (5) - B; 3+ + 3 I Ksp = LBPO [ +)3 8.1X10- (0.05) (35)3 8.18 10.0.05x2753 $35 162x1013 27 = 6x1019 = 0.84x10-6 mollutBi 31 T Bi cap) + 3 I lag kpp = [B, 3+] [ I ] 3 \I] = 0.76 14 Ksp = (3) (0.10) sa 8.181019 10.7013 -19 = 23.6 X 10 mol/L = 23

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