Question

A silver ring is composed of 1.02×1023 atoms.1.02×1023 atoms. Calculate the mass of the ring in grams.

Answer 1

1 mol of silver contains mass of 107.8 g.

We know ,

6.022 $\times$ 10²³ atoms of silver = 1 mol of silver

=> 1 atoms of silver = (1$\div$ 6.022 $\times$ 10²³) mol of silver

=> 1.02 $\times$ 10²³  atoms of silver = (1.02 $\times$ 10²³$\div$ 6.022 $\times$ 10²³) mol of silver = (1.02$\div$6.022) mol of silver

1 mol of silver contains mass of 107.8 g.

=>(1.02$\div$6.022) mol of silver contains mass of = 107.8 $\times$ (1.02$\div$6.022) g = 18.26 g