Question

Could I please have some help with these?

A11)

Ephoton = Ebind + Ekin

hc/delta = Ebind + 0.5mv^2/

I subbed in values provided and rearranged to find velocity.. It gave me a negative value.

(Ebind = 206000 J, h= 6.6261x10^-34, c= 2.99x10^8, delta = 215 x 10^9m)

A19) & A33) How would I go about these?

Thank you

Question A11. In a photoelectric effect experiment, what is the velocity of an electron emitted from a caesium (Cs) surface (Ebind = 206 kJ moll) by a photon with wavelength of 215 nm? A. 1.13 x 100 m s? B. 5.20 x 10' m s? C. 3.00 x 10ms1 D. 7.03 x 10ºm s E. 2.44 x 10m s?

Answer 1

A33. It has 3 isomers (c) is correct option

Ebina = 206x103 6-022x1023 = 3.42x1019 J Ephaton - her 6.626 X 10 34 x 3x108 2158159 9.25x10' J KEz śmu? 4.28x16'9- 3.42x1619 ~ 5.83x1019 = [5.83x1019 x 2 9. 10x10 31 = [1.13x106m/s (A) 19 overall Rxn 2NO+2H₂ → 2H₂O + Na - NO N CH) - d[H07. SINAT 3d - sve ono (E)