The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

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The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11.

Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A.

[H+]=[H+]=

MM

[H2A−][H3A]=[H2A−][H3A]=

Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA.

[H+]=[H+]=

MM

[HA2−][H2A−]=[HA2−][H2A−]=

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Answer 1

Answer #1

Solution : - that a Griven ka, @ - 3038 40 ka, 3727x108 kaz -4-178 10-17 (12 Mf13A] = 0.060 ty, eo • (H2A) (uz4] =006H0. Trip 00000000000 1573 + 3.38 X1017 0.06738 0.0000000000 1573 0.06738 0.00000 0000 0 23345 = 0.00001597.907065 = 1.52x10 4 tha hot ob Since Nazta. Že an Intermediate form; Karkas Na2HA) + kazko Kaz + (Na2HA] 17.27X10X4.17 XOXO.06H0 4:23 Hva e muita tuh x 0

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Answer 2

The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

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The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

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