Question

10. Write the condensed electron configuration for Ag*

Answer 1

Atomic number of Ag is 47.

E.C of Ag : 1 s ² , 2 s ², 2 p ⁶ , 3 s ², 3 p ⁶, 4 s ², 3 d ¹⁰ , 4 p ⁶ , 4 d ¹⁰ , 5 s ¹

Previous noble gas element in the periodic table is Kr with atomic number 36.  

Hence, its condensed E.C is [Kr] 4 d ¹⁰ , 5 s ¹

After loss of one electron Ag is converted into Ag ⁺ ion. Ag ⁺ contain 1 electron less than electrons present in Ag i e 46.

The valence shell is 5 and electron present in the 5 s sub shell will be lost , when Ag is ionized.

Therefore, we can write condensed E.C of Ag ⁺ ion as  [Kr] 4 d ¹⁰

ANSWER: condensed E.C of Ag ⁺ :  [Kr] 4 d ¹⁰