Problem 7 -:
(a)P = 350-0.08Q
TC = 2300 + 130Q. (1)
To find TR , we can use the price equation because P=AR.
P=AR=TR/Q
350-0.08Q = TR /Q
TR = (350-0.08Q)Q
TR = 350Q -0.08Q2. (2)
Price at eq level = MR =MC (at eq level)
To find MR and MC ,we need to differentiate TR and TC
d(TR)/dQ = MR = 350- 0.08Q
d(TC)/dQ = MC = 0+130
Equilibrium Price = MR = MC = 350-0.08Q = 130
0.08Q = 350-130
Q = 220/0.08
Q= 2750
Now put this value of Q in the Price equation
P=350-0.08Q
P = 350- 0.08(2750)
P= 350-220
P = 130 ANS (Price at profit maximisation)
Total Amount of Profit can be found out by
TR-TC approach - :
350Q-0.08Q2 - (2300+130Q)
350(2750) - 0.08(2750)2- 2300-130(2750) = Profit
Profit = 962500 - 605000 - 2300 - 357500
= -2300. (It shows loss)
b) 10% return on assets = 10% of 220,000,000
= 22,000,000
The amount of profit is below 10% as the profit in part a is a negative amount showing a loss.
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