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Problem 4 (24 points) Farmer Joe is planning to plant 30 hectares of rice, 40 hectares of wheat, and 30 hectares of cotton in
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Answer #1
LP Problem
Ha of Rice, Wheat and Cotton to be irrigated 100%, 80% and 60% to maximize profit
Subject to: Available land, and water

It can be shown as follows:

Maximize
190x(9R1+8.28R2+7.02R3
180x(12W1+10.56W2+9.6W3
240x(8C1+5.76C2+5.52C3

Where R1, R2, R3 is Ha of Rice irrigated at 100%, 80% and 60% respectively

Where W1, W2, W3 is Ha of Wheat irrigated at 100%, 80% and 60% respectively

Where C1, C2, C3 is Ha of Cotton irrigated at 100%, 80% and 60% respectively

Subject to

Land use

R1+R2+R3 = 30

W1+W2+W3 = 40

C1+C2+C3 = 30

Water use

1300(R1+0.8R2+0.6R3) + 1200(W1+0.8W2+0.6W3) + 1500(C1+0.8C2+0.6C3) <=125000

This is the solution we get in Excel, using Solver:

3.08 Ha of Rice at 100%, and 26.92 Ha of Rice at 80% irrigation

40 Ha of Wheat at 100% irrigation

30 Ha of Cotton at 100% irrigation

give $191,617 of profit

Land Used Production in tons / Ha Profit ($/ton)
Land used (ha) Water (m3/ha) Water demand @100% Irrigation @100% Irrigation @80% Irrigation @60% Subject to Irrigation @100% Irrigation @80% Irrigation @60% Profit Water
Rice 30 1300 39000          3.08        26.92 0 30 9 8.28 7.02 190                                          47,617 32000 30
Wheat 40 1200 48000        40.00              -   0 40 12 10.56 9.6 180                                          86,400 48000 40
Cotton 30 1500 45000        30.00              -   0 30 8 5.76 5.52 240                                          57,600 45000 30
Total required 100 132000                                       1,91,617 125000
Total available 100 125000
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