Homework Answers
2. Heat added = Mass of water * Specific heat of water * Temperature change + Calorimeter constant * Temperature change
4158 = 55 * 4.184 * (38.74 - 22.34) + C * (38.74 - 22.34)
Solving, C = 23.42 J / 0C
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2. We add 4.158 kJ of heat to a calorimeter that contains 55.0 g of water....
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