Question

When a scientist conducted a genetics experiments with peas, one sample of offspring consisted of 905 peas, with 683 of them having red flowers. If we assume, as the scientist did, that under these circumstances, there is a 3/4 probability that a pea will have a red flower, we would expect that 678.75 (or about 679) of the peas would have red flowers, so the result of 683 peas with red flowers is more than expected. a. If the scientist's assumed probability is correct, find the probability of getting 683 or more peas with red flowers. b. Is 683 peas with red flowers significantly high? c. What do these results suggest about the scientist's assumption that 3/4 of peas will have red flowers? . a. If the scientist's assumed probability is correct, the probability of getting 683 or more peas with red flowers is (Round to four decimal places as needed.)

Answer 1

Answer)

N = 905

P = 3/4

First we need to check the conditions of normality that is if n*p and n*(1-p) both are greater than 5 or not

N*p = 679

N*(1-p) = 226

Both the conditions are met so we can use standard normal z table to estimate the probability

Z = (x - mean)/s.d

Mean = n*p = 678.75

S.d = √{n*p*(1-p)} = 13.0264154701

We need to find

P(x>=683)

By continuity correction

P(x>682.5)

Z = (682.5 - 678.75)/13.0264154701

Z = 0.29.

From z table, P(z>0.29) = 0.3859

B)

Yes as the probability is greater than 0.05