Answer
The correct answer is "option a"
a. X=8, Y=6
Let
3X+2Y=36 be equation i
5X+4Y=64 be equation ii
multiplying
equation i by 5
equation ii by 3
3X+2Y=36 * 5
5X+4Y=64 * 3
we get
15X+10y= 180 let this be equation iii
15X+12y= 192 let this be equation iv
subtracting equation iv from equation iii
+15X+10y= 180
-15X-12y= -192
-----------------
-2Y=-12
Y=6
Substituting value of Y in equation i
3X+2Y=36
3X+2(6)=36
3X+12=36
3X=36-12
3X=24
X=8
So the solution is (8,6)
_01. Which of the choices below constitutes a simultaneous solution to these equations? (2 pts.) (1)...
4. a. Which choice is a simultaneous solution of these two equations: 3x + 4y = 10 and 5x + 4y = 14 x = -1, y = -2 x = 2, y = 1 y=2x x=y x=1,y=2 b. Which choice is a simultaneous solution of these two equations: 30x + 40y = 100 and 50x + 40y = 140 x=-1,y=-2 x=2,y=1 y=2x x=y x=1,y=2 c. Which choice is a simultaneous solution of these two equations: 2x + y...
need all questions answered as soon as possible i have an
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study. im having a lot of trouble answering the problems and need
to see hpw it is done. thank you.
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