Consumers spend an average of $13.80 on a meal at a restaurant. Assume that the amount spent on a restaurant meal is normally distributed and the standard deviation is $2.00.
Please don't hesitate to give a "thumbs up " for the answer, in case you're satisfied with it.
The top 10% means we have P(X<c) = .90
So, lets use Z tables to find the Z value for which cumulative probability is .90, it is 1.282
Z= 1.282
So, (c-13.8)/2 = 1.282
c = 1.282*2+13.8
= 16.364 or option D is correct. $16.36
Answer is D
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