Question

HW 5-Due date: November 13, 2019 For each problem only answer those parts that are listed below not all parts. 4.63: (e) 4.65: (c) 4.71: (c) 4.83: (a) 4.119: (b) 4-63. Use Appendix Table III to determine the following probabilities for the standard normal random variable Z (a) P(Z<1.32) (c) P(Z>1.45) (e) P-2.34<Z<1.76) (b) P(Z<3.0) (d) P(Z>-2.15) 4-65. Assume that Z has a standard normal distribution. Use Appendix Table III to determine the value for z that solves each of the following: (a) P(Z<z) 0.9 (b) P(Z<z)= 0.5 (c) P(Z>z) 0.1 (d) P(Z>z)= 0.9 (e) P(-1.24<Z<z)=0.8 4-71. The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6000 kilo-

Answer 1

4.63)

e) P (    -2.340   < Z <    1.760   )                       
= P ( Z <    1.760   ) - P ( Z <   -2.340   ) =    0.9608   -    0.0096   =    0.9512   (answer)

4.65)

c) P(Z>z) = 0.1

P(Z≤z) = 1 - 0.1 = 0.9

Z value at    0.9   =   1.282   (excel formula =NORMSINV(   0.9   ) )

value of z =1.282

please revert..