Question

A six sided die is tossed. Consider the following events, A: the event that a number more than 4 is rolled B: the event that a odd number is rolled Find AnB

Answer 1

A six sided die is tossed,

Let A be the event that a number more than 4 is rolled

Let B be the event that a odd number is rolled.

There are, 2 numbers are more than 4 when rolling a six sided die, which are { 5, 6 }and 3 odds numbers are, { 1, 3, 5}

we want to find, $(A \cap B)$

A = { 5, 6 } and B = { 1, 3, 5}

Therefore,

$(A \cap B) = \{ 5 \}$