ANSWER:-
a)-first we have to calculate the theoretical yield of of Fe
molecular weight of Fe2O3 is 159.6 gm and given weight is 150 g moles of Fe2O3 is one
molar mass of Fe is 55.8 g moles of Fe is 2 ,
so,
150 g Fe2O3 * 1 mole Fe2O3/159.6 g * 2 mole Fe / 1 mole Fe2O3 * 55.8 g Fe/1 mole Fe
=104.9 g of Fe (theoretical yield)
b)- percent yield = actual yield/theoretical yield * 100
= 87.9 g/104.9 g *100
percent yield = 83.79 %
Problem 5.6. The canal bringing water from Kurtboğazı Dam to Ankara is 10! km long, before...
You must show work in order to receive credit. Make sure to include units and indicate your final answer by putting a box around your final answer. If you do not box in a response, I will count it as no final answer and you will lose points! 1. Mining companies use this reaction to obtain iron from iron ore: Fe2O3(s) + 3 CO(g) + 2 Fe(s) + 3 CO2(g) The reaction of 167 g Fe2O, with 85.8 g CO...