Question

TELJU IM NaOH + IM HCI - 0.00027-9 Volume of NaOH 50.om 71.000 27. 2.000 27 Volume of HCI 5o.om 3.000 27. Total volume after mixing loom 61.000 127. 5.000 127 net ionic equation CH3.coo Haeltok 799) > CH3 (00 27.83 (timss terme T, = 33.36 AT - T, - T, - 0.000 27.3 5.33 1oooo 127. 9- AH 2.000 Calculation 3.000 Ma nemoll => 1HCl =VhcloMao-csxla. sf.ooo M Not-o-osonal 5.000 12 B=ME AT - Q = 4.185 x 800g.x. 5053 = 2314.305

can i pleas get help in how to do the calculation.

Answer 1

Volume of NaOH = 50.00 ml Volume of HU 50.00 mL Total volume after mining: 100 ml T, = 27.83c; T = 83.36°C AT = 5.53 0 q = MCAT m Total mass of resultant solutions. Cu specific heal capacity of the solution. Change in enthalpy: Hneach : 9 no. of moles of limiting reactant (Ha) Molarity : M = n 1= n 0.05 Volume (no. of moles of limitoy) n = 0.05 moles. reactant assumed spuific heat : 4:18 Jlg c. m 100 g as density: Igine g100x 4.18 x 5.53 9311.54 4H.q . 2311:54. 46, 230-8 J ñ 0.05 46.23 kJ