Question

The Ksp of CaSO4 is 6.1x10-9. For 1.0 L of a 0.0010 M Ca(NO3), solution, how many moles of Na, SO4 need to be added to initia
0 0
Add a comment Improve this question Transcribed image text
Answer #1

5 As we know that . ionic product < Ksp ionic product = kep ionic produel > ksp sclection is unsaturated. solution is saturatThus. 1 - 0.0010 [Ca 2+ ] [sou akso 0.0010 [sour] > 6.18105 [sou ] } 6.18155 [Son] 20.061 m. 20.061 mol since volume is not c

Add a comment
Know the answer?
Add Answer to:
The Ksp of CaSO4 is 6.1x10-9. For 1.0 L of a 0.0010 M Ca(NO3), solution, how...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 30 (2.5 points) How many moles of Ca(NO3)2 must be added to 1.0 L of...

    Question 30 (2.5 points) How many moles of Ca(NO3)2 must be added to 1.0 L of a 0.203 MKF solution to begin precipitation of CaF2? For CaF2, Ksp = 4,0 10-11 4.9 x 10-16 02x10-10 O 16 x 10-12 09.7x10-46 3.1 10-6

  • An aqueous solution has 0.0026M Ca(NO3)2 (aq) and 0.0016M KSO4 (aq). Ksp [CaSO4] = 2.4 ×...

    An aqueous solution has 0.0026M Ca(NO3)2 (aq) and 0.0016M KSO4 (aq). Ksp [CaSO4] = 2.4 × 10-5 Ksp [CaC2O4] = 2.3 × 10-9 What describes the system best? Q > Ksp and no precipitate forms Q < Ksp and a precipitate forms Q < Ksp and no precipitate forms Q > Ksp and a precipitate forms Q = Ksp and the solution is saturated

  • The concentration of Ca 2+ and SO4^2- in a saturated solution is 7.02x10^-3 moles/L calculate the...

    The concentration of Ca 2+ and SO4^2- in a saturated solution is 7.02x10^-3 moles/L calculate the ion concentrations immediately after addition of 1mL Na2SO4: Given: Ksp [CaSO4] = 4.93 x 10^-5, Solubility of CaSO4 = 0.956 g/L, Concentration of Na2SO4 = 2.0 x 10^-2 moles/L #1 [Ca2+] in 2mL of solution in Test tube A = .....moles/L #2 [SO4^2-] in 2mL of solution in Test tube A = .....moles/L #3 Calculate Q for the ion product [Ca2+][SO4^2-] in the solution:...

  • 3 pts Question 34 As a mixed 1.0-L solution that is 0.10 M in each of...

    3 pts Question 34 As a mixed 1.0-L solution that is 0.10 M in each of Ba(NO3)2 Ca(NO3)2 and Pb(NO3)2 has 0.0050 M Na Cro4 added dropwise to it, which would precipitate first? OCacro OPbCros BaCro O none of these would precipitate, they are soluble salts

  • How many moles of nitrate ion are in 1.0 L of a 8.8 M Mg(NO3)2 solution?

    How many moles of nitrate ion are in 1.0 L of a 8.8 M Mg(NO3)2 solution?

  • A solution of 0.5 M lead(II) nitrate, Pb(NO3)2(aq) is added to an equal volume of 1.0...

    A solution of 0.5 M lead(II) nitrate, Pb(NO3)2(aq) is added to an equal volume of 1.0 M sodium iodide, NaI(aq), and lead(II) iodide precipitates, PbI2(s). What is the molar concentration of lead ions, Pb2+(aq), that remains in solution? [FWPbI2 = 461.01 g/mol, Ksp = 1.4 x 10−8]? Assume 298 K.

  • Consider 1.0 L of a solution which is 0.80 M HF and 0.55 M NaF (K...

    Consider 1.0 L of a solution which is 0.80 M HF and 0.55 M NaF (K for HF - 7.2x104). Part 1 Calculate the pH of this solution. pH- Part 2 Calculate the pH after 0.10 mol of HCl has been added to the original buffer solution. Assume no volume change on addition of HCI. pH- Part 3 Calculate the pH after 0.20 mol of NaOH has been added to the original buffer solution. Assume no volume change on addition...

  • 200 mL of 0.0010 M Sr(NO3)2 (aq) are mixed with 800 mL of 0.0050M NaF (aq)...

    200 mL of 0.0010 M Sr(NO3)2 (aq) are mixed with 800 mL of 0.0050M NaF (aq) to make 1.0 L of solution. The Ksp value of SrF2 is 4.3 x 10-9. Which is correct? I know the answer, I just don't know how they got to it. a. SrF2 will not precipitate. b. SrF2 will precipitate. NaF is the limiting reactant. c. SrF2 will precipitate. NaNO3 is the limiting reactant. d. SrF2 will precipitate. Sr(NO3)2 is the limiting reactant. e....

  • A)A volume of 46.2 mL of a 0.568 M Ca(NO3)2 solution is mixed with 75.5 mL...

    A)A volume of 46.2 mL of a 0.568 M Ca(NO3)2 solution is mixed with 75.5 mL of a 1.496 M Ca(NO3)2 solution. Calculate the concentration of the final solution. Calculate the molarity of each of the following solutions. (b) 7.25 g of methanol (CH3OH) in ×  102 mL of solution: mol/L (c) 9.68 g of calcium chloride (CaCl2) in 2.20 × 102 mL of solution: mol/L (d) 8.57 g of naphthalene (C10H8) in 85.2 mL of benzene solution: mol/L

  • Isnt the molar solubility of Ca(OH)2 with added CaCl2 supposed to be less than the molar solubili...

    isnt the molar solubility of Ca(OH)2 with added CaCl2 supposed to be less than the molar solubility of Ca(OH)2 by itself? where did I mess up? A. Molar Solubility and Solubility Product of Calcium Hydroxide メーーー Desk No. Trial 1 Trial 2 Trial 3 1. Volume of saturated CalOHD, solution (ml) 2. Concentration of standardized HCI solution (mol/L) 3. Buret reading, initial (mL) . 4. Buret reading,final(mL) 5. Volume of HCI added (mL) 6. Moles of HCl added (mol) 7....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT