Question

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Answer 1

According to the HOMEWORKLIB POLICY I am solving first question.

(1) Given that, Moles of gas (m) = 1.345 moli Volume of the vessel CV) = 2.00l. = 2.000 103 m3 Pressure (P) = 1601.5 mmHg. = 1681.5 X 13.332 Nom-2 - 22418).594 Nm-z Since 12= 10-3 m3 and 1 mmHg = 13.332 N2529 For an ideal gas, the kinetic energy com be written as, K'E CE) = 3PV ----Ci) Substitute the given values in equ. cis as follows: F 3x(224181.594 N- m x (2:00 x1033) 2x 1.345 mol 2n TE = 500.033 Jamal -1 Answer:- The kinetic energy of the gas is 500.033 Jamot.

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