What is the pH of 450.0 mL of an aqueous solution containing 0.839 g of HCl?
![[HCe] = 0.839 - 36.580.450 = 0.05108 M Hee is strong acid, hence dissociate completely. U Hee Ht + ce 0.05108m 0.05100M pH =](http://img.homeworklib.com/questions/138a6040-78e7-11ea-9a8b-4d69733f97de.png?x-oss-process=image/resize,w_560)
What is the pH of 450.0 mL of an aqueous solution containing 0.839 g of HCl?
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