Answer:
Part 1: Completed table is given below:
| Abatement | Pollution | MSB | MSC | Social TB | Social TC | Social NB |
| 0 | 50 | 65 | 5 | 65 | 5 | 60 |
| 10 | 40 | 55 | 20 | 120 | 25 | 35 |
| 20 | 30 | 45 | 45 | 165 | 70 | 0 |
| 30 | 20 | 35 | 60 | 200 | 130 | -25 |
| 40 | 10 | 25 | 65 | 225 | 195 | -40 |
| 50 | 0 | 15 | 70 | 240 | 265 | -55 |
Calculations:
1. Social total benefit (TB) is the MSB plus the MSB for the previous abatement.
The first value will be the same as MSB (65). The second value of ST will be 65 plus the next value of MSB (65 + 55 = 120), The successive values will be: (120+45 = 165), (165 + 35 = 200). (200 + 25 = 225), (225 + 15 = 240)
2. Social total cost (TC) will be calculated like above, but for MSC values. So first value is same as MSC (5). The second value will be (5+20 = 25), subsequent values are: (25 + 45 = 70), (70 + 60 = 130), (130 + 65 = 195), (195 + 70 = 265)
3. Social net benefit (NB) is the difference between MSB and MSC, that is, benefit over cost:
formula: MSB - MSC. So the values will be: (65 - 5 = 60), (55 - 20 = 20), (45 - 45 = 0), (35 - 60 = -25), (25 - 65 = -40), (15 - 70 = -55)
Part 2:
The graph of MAB and MSC is:

Part 3:
From the table, we see that MSB = MSC = 45 when abatement is 20 and pollution 30.
From the graph we see that MSB curve intersects MSC curve at 45, and abatement at 20. From the table we know that when abatement i 20, pollution is at 30.
So, optimum level of abatement is 20 and pollution 30.
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