Solution:
With price per unit of output = £2 per unit
Total revenue = price*quantity
TR = 2*q = 2*(305x - 2x2)
TR = 610x - 4x2
Cost (the variable part) = price of variable input*quantity of variable input
C = 10*x
Assuming fixed cost to be $F.
Total cost = variable cost + fixed cost
TC = 10x + F
(Note that amount of fixed cost has no impact on optimal level of variable factor to be used).
So, profit, Z = total revenue - total cost
Z = 610x - 4x2 - 10x - F
Z = 600x - 4x2 - F
Optimal amount of x can be found using first order condition: dZ/dx = 0
dZ/dx = 600 - 2*4x - 0
dZ/dx = 600 - 8x
Then, using FOC: 600 - 8x = 0
So, x = 600/8 = 75 units
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