Question

Box 15-2 Kilocalorie Adjustment Necessary for Weight Loss 454 g (1 lb) per week there needs to be a 500 kcal To lose 454 g (1 energy deficit per day. BASIS OF ESTIMATION: 1 lb of body fat = 454 g 1 g of pure fat = 9 kcal of body fat = 7.7 kcal (differences due to water in fat cells) 254 9 x 7.7 kcal/g = 3496 kcal/454 g of body fat (or -3500 kcal) 500 kcal energy deficit x 7 days = 3500 kcal = 454 g of body fat = 1 lb Box 15-3 Estimation of Adult Energy Needs MIFFLIN-ST. JEOR EQUATION Men Total Energy Expenditure (kcal/day) = (Weight (kg) x 10+ Height (cm) x 6.25 - Age x 5 - 5) x Physical activity coefficient Women Total Energy Expenditure (kcal/day) = (Weight (kg) x 10+ Height (cm) x 6.25 - Age x 5 - 161) Physical activity coefficient PHYSICAL ACTIVITY COEFFICIENT 1.200 = Sedentary little or no exercise) 1.375 = Lightly active (light exercise or sports 1 to 3 days per week) 1.550 = Moderately active (moderate exercise or sports 3 to 5 days per week) 1.725 = Very active (hard exercise or sports 6 to 7 days per week) 1.900 = Extra active (very hard exercise or sports and physical job)

Answer 1

1 . According to Muffin saint joer equation Saarah needs 6837 kilo calories of total energy needs as per daily requirement.

2. Her total energy need can be compared with her daily requirement based up on the energy needs and the daily work Saarah was involved with.

3. Saarah has to reduce 500 kilo calories per day that is she has to take 2000 kilo calories per day.

4. As Saarah is living most sedentary life, to create a negative energy balance she can start some jim activities and also can involve in work which reduces the formation and accumulation of body fat.