We can solve the sum of an Arithmetic Progression equation to calculate the annual increase in CF:


d = to the annual increase in previous year's CF to bring the final CF to 450000 in year 10


So the CF should increase by 40000 every year:
| Year | CF |
| 1 | 90000 |
| 2 | 90000+40000 = 130000 |
| 3 | 130000 +10000 = 170000 |
| 4 | 170000 + 40000 = 210000 |
| 5 | 210000 + 40000 = 250000 |
| 6 | 250000 + 40000 = 290000 |
| 7 | 290000 + 40000 = 330000 |
| 8 | 330000 + 40000 = 370000 |
| 9 | 370000 + 40000 = 410000 |
| 10 | 410000 + 40000 = 450000 |
CF Diagram is as follows:

Arithmetic gradient is equal to the annual increase of 40000
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